Question

23. A force of (4x2 + 3x) N acts on a particle
which displaces it from x = 2m to x = 3m.
The work done by the force is​

Answer 1

Answer:

$\int\limits^a_b {f(x)} \, dx =work$

Explanation:

So by the above formula we can say that

$\int\limits^3_2 {4x^{2}+3x } \, dx =4/3x^{3} +3/2x^{2} limits from 2 to 3$

so on solving we get 4/3(27-8)+3/2(9-4)

so on solving everything we get 197/6=32.83 N

Hoping this information can help you.

Answer 2

Answer:

solved and explained. hope it will help