Question

23
A force of 98 N is required to just start moving a body of mass 100 kg over ice. The coefficient of static
friction is
1) 0.6
2) 0.4
3) 0.2
4) 0.1​

Answer 1

Answer:

0.1

Explanation:

F = Coefficient of friction * mass * g

98 = x * 100 * 9.8

980x = 98

x = 98/980

x = 1/10

x = 0.1

Answer 2

$\huge{\bold{\underline{\underline{....Answer....}}}}$

$\huge{\bold{\underline{Given:-}}}$

• Force required to move = 98N.
• Mass of Ice = 100Kg.
• g = 9.8 m/s².

$\huge{\bold{\underline{Explanation:-}}}$

As the Force of magnitude "98N" is required to just start the body,

therefore, the Force of friction(f) will be equal to External Force.

$\large{\bold{F = f}}$

$\large{ \implies f = 98 \: N}$

Normal force on the body,

$\large{N = mg}$

$\large{N = 100 \times 9.8}$

$\large{N = 980N}$

Now, Applying the formula,

$\large{\bold{f = \mu_sN}}$

Substituting the values,

$\large{98 = \mu_s \times 980}$

$\large{ \mu_s = \dfrac{98}{980}}$

$\large{ \mu_s = \dfrac{ \cancel{98}}{ \cancel{980}}}$

It comes as,

$\huge{\boxed{\boxed{ \mu_s = 0.1}}}$

So, the coffecient of static friction is 0.1.