23. A geometric progression (GP) consists
of 200 terms. If the sum of odd terms
of the GP is m, and the sum of even
terms of the GP is n, then what is its
common ratio ?
(a) m/n
(b) n/m
(c) m + (n/m)
(d) n+(m/n)
Answers
Common Ratio = n/m if in a GP of 200 terms sum of odd terms = m & sum of even terms = n
Step-by-step explanation:
Let say GP is
a ar ar² ar³ ............................................ar¹⁹⁹
odd term
= a ar² ar⁴ ....................................ar¹⁹⁸
Sum of odd term = a ( (r²)¹⁰⁰ - 1)/(r² - 1) = m
Even Terms
ar ar³ ....................................ar¹⁹⁹
Sum of odd term = ar ( (r²)¹⁰⁰ - 1)/(r² - 1) = n
=> r * a ( (r²)¹⁰⁰ - 1)/(r² - 1) = n
=> r * m = n
=> r = n/m
Common Ratio = n/m
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Answer:
The answer is n/m
Step-by-step explanation:
Divide this gp into 2 parts 1 of even and other be odd terms' gp then do apply sum formula and ur answer will come.......