23. a. How many atoms of oxygen is present in 1mole of oxygen and how many grams of
oxygen is required for it?
b. Calculate the number of moles in 28g of nitrogen
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Answer:
a. One mole of oxygen contains 6.022×1023 molecules or 2×6.022×1023 atoms of oxygen. Its weight is equal to molecular weight which is 32 g/mol.
b. In the sum, number of moles = 2 As the given element is nitrogen, its atomic weight is 14. Substituting the values in the formula, it gives Mass of 2 moles of nitrogen atom = 2 × 14 = 28g
Explanation:
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