Question

23. A man borrows Rs 8,000 at a compound interest rate of 10% per annum. If he repays Rs 1,500 at the end of the first year and Rs 2,000 at the end of the second year, find his outstanding loan at the beginning of the third year. please jaldi and the is answer is also I mention 6,030
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Answer 1

Step-by-step explanation:

Amount to be paid at the end of two years will be =Amountafter2years=8000(1+

Amount to be paid at the end of two years will be =Amountafter2years=8000(1+ 100

Amount to be paid at the end of two years will be =Amountafter2years=8000(1+ 10010

Amount to be paid at the end of two years will be =Amountafter2years=8000(1+ 10010

Amount to be paid at the end of two years will be =Amountafter2years=8000(1+ 10010 )

Amount to be paid at the end of two years will be =Amountafter2years=8000(1+ 10010 ) 2

Amount to be paid at the end of two years will be =Amountafter2years=8000(1+ 10010 ) 2 =8000(1.1)

Amount to be paid at the end of two years will be =Amountafter2years=8000(1+ 10010 ) 2 =8000(1.1) 2

Amount to be paid at the end of two years will be =Amountafter2years=8000(1+ 10010 ) 2 =8000(1.1) 2 =8000(1.21) =9680 Amount already paid in 2 years is(3200+1500)=4700 Therefore amount of loan outstanding at the beginning of third year will be(9680−4700)=4980

Answer 2

Answer:

6030

ok see the picture which I had give