23 A missile is fired for maximum range with an initial
velocity of 20 m/s. If g = 10 m/s2, the range of missile is
CBSE AIPMT 2011
(a) 50 m
(b) 60 m
(c) 20 m
(d) 40 m
Answers
Answered by
4
Answer:
(d) 40m
Explanation:
As we know that,
For maximum range of a projectile the angle is 45°.
Therefore,
R= u^2×sin(2×45)/g
or
20×20×sin90°/10
or
40m
Answered by
0
Dear student,
Given :-
- velocity = 20 m/s
- g = 10 m/s
- maximum range, ∅ = 45°
To find :-
- The range of missile
Solution :-
We know for the horizontal range from the concept of projectile motion that;
R = u²sin(2∅)/g
Putting the given values in the above equation, we obtain;
R = (20)² sin 90° / 10
R = 400/ 10
R = 40 m
Hence, the range of the missile is 40 m.
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