23. A potentiometer wire has a length of 10 m and a resistance of 4 ohm .It is connected in series
with a cell of emf 10 V and internal resistance 1 ohm Calculate the balance length obtained for
the cell of emf 3 volt.
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Answer:
R=resistance of potentiometer wire=10Ω
L=length of potentiometer wire=10m
r=internal resistance of cell=1Ω
V=emf of cell=11V
Effective resistance of circuit=R
eq
=R+r
⟹R
eq
=10+1=11Ω
Current in circuit=I=
R
eq
V
=
11
11
⟹I=1A
Potential difference across ends of potentiometer wire AB=V
o
=IR
⟹V
o
=1×10=10V
Potential gradient of potentiometer=
L
V
o
=
10
10
=1V/m
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