Math, asked by sahilkingkhan90574, 2 months ago

23. A rectangular park 60m long and 40m wide has two pathways of equal width
running in the longitudinal and transverse direction and crossing each other at
right angles in the middle of the park. The rest of the park is used as lawn. if the area of the lawn is 2019 sq.m, then what is the width of the pathway?
a. 2.5m
b. 3m
с. бm
d. 4.5m​

Answers

Answered by Hitanshu100
0

Answer:

Area of the park = (60 x 40) = 2400m2

Area of the lawn = 2109m2

Area of the crossroads = (2400 - 2109) = 291m2

Let the width of the road be x metres. Then,

60x+40x-X2=291

x2-100x+291=0

(x - 97)(x - 3) = 0

x = 3.

Answered by thegopsgp
0

Answer:

Step-by-step explanation:

Area of the park = (60 x 40) = 2400m2

Area of the lawn = 2109m2

Area of the crossroads = (2400 - 2109) = 291m2

Let the width of the road be x metres. Then,

60x+40x-X2=291

x2-100x+291=0

(x - 97)(x - 3) = 0

x = 3.

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