Question

23.(a) Two bodies of equal masses move with uniform velocities v and 3v respectively. Find the ratio of

their kinetic energies.

(b) On what factors does kinetic energy of a body depend?

(c) A bullet of mass 10 g is fired with a velocity of 80m/s.What is its kinetic energy?​

Answer 1

Answer:

Invalid expression

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Answer 2

Answer:

a) Mass of first body = m

Velocity of the first body = v

Mass of second body = m

Velocity of second body = 3v

The ratio of kinetic energies of the two bodies

= (Kinetic energies of second body)/(Kinetic energies of first body)

= (1/2)mv² / (1/2)m(3v)²

= (1/2)mv² / (9/2)mv²

= 1/9

The ratio of the kinetic energies = 1:9

b) The kinetic energy of a body or object depends

upon its velocity and mass.

c) mass = 10g = 0.1kg

velocity = 80m/s

Kinetic energy = 1/2mv²

= (1/2)×0.1×(80)²

= (1/2)×0.1×6400

= 3200×0.1

Kinetic energy = 320 J

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