Question

23. आकृति में, DE || AP और DP || AC हो, तो सिद्ध कीजिए किBE/EP=BP/PC In figure, DE || AP and DP || AC Prove that BE/EP=BP/PC​

Answer 1

the answer is in the attachment

Answer 2

Answer with Explanation:

In triangle BPA

DE is parallel to AP

Reason: Given

By triangle proportionality theorem

$\frac{BE}{EP}=\frac{BD}{DA}$...(1)

In triangle BCA

Given: DP is parallel to AC

By triangle proportionality theorem

$\frac{BP}{PC}=\frac{BD}{DA}$...(2)

By equation (1) and equation (2)

We get

$\frac{BE}{EP}=\frac{BP}{PC}$

Hence, proved.

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