Question

23. Acceleration of a body is given by the equation
a = (4 - 3v) m/s2 Speed v is in m/s and t is in
second. If initial velocity is zero then terminal
velocity of the body is
(1) 3 m/s
(2) 7
m/s
(3) 4 m/s
(4) Infinite
Aakash Educational Services Limited - Regd. Office : Aakash​

Answer 1

Explanation:

Let,

The given equation of acceleration of a body, V= (4-3v)m/s^2

Initial Velocity, u= 0 m/s^2

We know, at terminal velocity, V=0

So, 4-3v=0

√ 3v= 4

√ v= 4/3

√ v= 1.33

Terminal velocity 1.33 m/s^2. (Ans)

Answer 2

Answer:

4 m/s is the answer I think