Question

23. Calculate the resultant resistance in the given circuits.
6 Ω
6Ω Γ
6 Ω
6Ω
ε ε ε
6 Ω
6 Ω
(a)​

Answer 1

Answer:

First, what's the equivalent resistance of the 3Ω and 6Ω resistors? Using the quick method, it's

(3×6)÷(3+6) or 2Ω

So your circuit's effectively 3Ω in series with 2Ω, 5Ω in total.

Current according to Ohm's Law is

I=V/R

V = 5V, R = 5Ω so I = 1A So, Ohm's Law again to calculate the voltage drop across the 3//2 combination,

V = IR, I is 1, R is 2, so the answer's 2V.