Question

23 cm
5 The height of an equilateral triangle is 9 cm.
Find the area of the triangle.​

Answer 1

CORRECT QUESTION :

• The height of an equilateral triangle measures 9cm. Find its area, correct upto 2 places of decimal. Take √3 = 1.732cm

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ANSWER:

$\begin{gathered}\begin{gathered}: \implies \underline{ \boxed{\displaystyle \sf \bold{\: Height \: = \: \frac{ \sqrt{3} }{2} \: (side) \: = \: 9}} }\\ \\\end{gathered}\end{gathered}$

$\begin{gathered}\begin{gathered}\dashrightarrow \displaystyle \sf \: Side\:=\: \frac{18}{ \sqrt{3} } \\ \\ \\\end{gathered}\end{gathered}$

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Now ,

$\begin{gathered}\begin{gathered}: \implies \underline{ \boxed{\displaystyle \sf \bold{\:Area \: = \: \frac{ \sqrt{3} }{4 } \: {(side)}^{2} }} }\\ \\\end{gathered}\end{gathered}$

$\begin{gathered}\begin{gathered}: \implies \displaystyle \sf \: \frac{ \sqrt{3} }{4 } \: \times \: \frac{18}{ \sqrt{3} } \times \frac{ 18}{ \sqrt{3} } \\ \\ \\\end{gathered}\end{gathered}$

$\begin{gathered}\begin{gathered}: \implies \displaystyle \sf \: 3 \sqrt{3 } \: \times 9 \\ \\ \\\end{gathered}\end{gathered}$

$\begin{gathered}\begin{gathered}: \implies \displaystyle \sf \: 3 \: × \: 1.732 \: \times 9 \\ \\ \\\end{gathered}\end{gathered}$

$\begin{gathered}\begin{gathered}: \implies \displaystyle \sf \: 5.196 \: \times 9 \\ \\ \\\end{gathered}\end{gathered}$

$\begin{gathered}\begin{gathered}: \implies \underline{ \boxed{\displaystyle \sf \bold{\:46.964\: cm^2 }} }\\ \\\end{gathered}\end{gathered}$

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So, the area is 46.964 cm²

Answer 2

Answer:

CORRECT ANSWER ⬆⬆⬆⬆

Step-by-step explanation: