Question

23. Describe the motion of a body which is accelerating at a constant rate of 10 m s2. If the body starts from rest,
how much distance will it cover in 2 s?
24. A motorcycle moving with a speed of 5 m/s is subjected to an acceleration of 0.2 m/s2. Calculate the speed of
the motorcycle after 10 seconds, and the distance travelled in this time.
25. A bus running at a speed of 18 km/h is stopped in 2.5 seconds by applying brakes. Calculate the retardation
produced
26. A train starting from rest moves with a uniform acceleration of 0.2 m/s2 for 5 minutes. Calculate the speed
acquired and the distance travelled in this time.​

Answer 1

Answer:

Check Explaination

Explanation:

23. Acceleration = 10 m/s2

Initial Velocity = 0

2 seconds:

Time = 2

s = ut+1/2at^2

solving for s: > 0x2 + 1/2at^2

> 0 + 5x4

>20 meters

ans: 20 m

24. u = 5m/s

a = 0.2

t = 10s

s = ?

solving for s:

s = ut+1/2at^2

s = 50+0.1x100

s = 60 Meters

Ans: 60 m

25. u = 18km/h

v = 0

t = 2.5 s

retardation = negative acceleration.

a = v-u/t

a = -18/2.5

a = -7.2

retardation = 7.2 km/hr^2

ans: 7.2 km/hr^2

26. u = 0

a = 0.2m/s^2

t = 5 minutes (300 s)

solving for v and s

s = ut+1/2at^2

s = 9000 m

Distance = 9 KM / 9000m

v =>

a = v-u/t

v = u+at

v = 0+0.2x300

v = 60kmph