Question

23. Find all pairs of consecutive odd positive integers both of which are smaller than
10 such that their sum is more than 11.
​

Answer 1

ANSWER:

Let x be the smaller of the two consecutive odd positive integers. Then, the other integer is x+2. Since both the integers are smaller than 10.

x + 2 < 10

⇒x < 10 − 2

⇒x < 8 ..... (i)

Also, the sum of the two integers is more than 11.

∴x + ( x + 2 ) > 11

⇒2x + 2 > 11

⇒2x > 11 − 2

⇒2x > 9

⇒x > 9/2

⇒x > 4.5 ...... (ii)

From (i) and (ii), we obtain

Since x is an odd number, x can take values, 5 and 7.

Thus, the required possible pairs are (5,7) and (7,9).

PLEASE MARK AS BRAINLIEST ANSWER

Answer 2

Answer:

give thanx take thanx

i hope my answers help you