Question

23.
Find the area of the trapezium whose parallel sides are 14cm and
10cm and whose height is 6cm.
​

Answer 1

Answer:

Area of trapezium = (1/2) x h x (a + b) Here a = 14 cm, b = 10 cm, h = 6 cm Hence area trapezium = (1/2) x 6 x (14 + 10) = 3 x 24 = 72 sq cm

pls follow me and mark my answer as brainliest

Answer 2

Given :-

Parallel sides of the trapezium = 14cm and 10cm

Height of the trapezium = 6 cm

To Find :-

The area of the trapezium.

Analysis :-

Substitute the given values in the formula of area of trapezium.

Then solve and find the value accordingly.

Solution :-

We know that,

• h = Height
• a = Area

By the formula,

$\underline{\boxed{\sf Area \ of \ trapezium= \dfrac{Base + Base}{2} \times Height}}$

Given that,

Parallel sides = 14cm and 10cm

Height (h) = 6 cm

Substituting their values,

$\sf =\dfrac{14+10}{2} \times 6$

$\sf =12 \times 6$

$\sf =72 \ cm^2$

Therefore, area of the trapezium is 72cm².