(23) Find the coordinates of a point A, where AB is the
diameter of a circle whose centre is (2, -3) and B is
(1, 4). (Chp.7)
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Answer:
A = ( 3 , -10)
Step-by-step explanation:
mid point = (2, -3) and B = (1, 4). A = ( x1 , y1)
we can use mid point formula
(x1 + 1 ) /2 = 2 , (x1 + 1 ) = 4 , x1 = 3
(y1 + 4 ) /2 = -3 , (y1 + 4 ) = -6 , y1 = -10
A = ( 3 , -10)
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