Math, asked by Anonymous, 9 months ago

23. Find the greatest number that will divide 43, 91 and 183 so as to leave the same remainder in each case.


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step by step answers plzz​

Answers

Answered by xttiiittugtdg
7

Answer:

The greatest number that divide 43, 91 and 183 and leave the same remainder is 4

Step-by-step explanation:

All three number is 43, 91 and 183.

The largest no. is 183

The smallest no. is 43

Subtract smallest number from both the highest numbers.

So,

183 - 43 = 140

91 - 43 = 48

91 is smaller than 183, So subtract 91 from 183.

183 - 91 = 92

Now, we have three number: 140, 48 and 92.

So, the HCF of 140, 92 and 48 is 4.

So, the highest number that divide 183, 91 and 43 and leave the same remainder is 4.

Hope it helful

Answered by nakulathul
2

Answer: hope this helps

The greatest number that divide 43, 91 and 183 and leave the same remainder is 4

Step-by-step explanation:

All three number is 43, 91 and 183.

The largest no. is 183

The smallest no. is 43

Subtract smallest number from both the highest numbers.

So,

183 - 43 = 140

91 - 43 = 48

91 is smaller than 183, So subtract 91 from 183.

183 - 91 = 92

Now, we have three number: 140, 48 and 92.

So, the HCF of 140, 92 and 48 is 4.

So, the highest number that divide 183, 91 and 43 and leave the same remainder is 4.

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