Question

23.
Find the quadratic polynomial whose zeroes a and Bare such that a + B = 5 and
2a - B = 4.​

Answer 1

Answer:

Step-by-step explanation:

Given that,

a + b = 5⇒a = 5 - b

2a + b = 4 ⇒Now put " a = 5 - b " value in " 2a + b = 4 " , we get

2 ( 5 - b ) + b = 4 ⇒ 10 - 2b + b = 4 ⇒10 - b = 4 ⇒10 - 4 = b ⇒b = 6

Now put " b = 6 " value in " a + b = 5 " , we get

a + 6 = 5 ⇒ a = 5 - 6 ⇒a = - 1.

Now we have a= - 1 and b = 6

The quadratic equation = ax^2 + bx + c = -x ^2 + 6x + 0 is the answer.