Math, asked by ayushmehra2112, 10 months ago

23. Find the ratio in which the join A(2,1,5) and B(3,4,3) is divided by the plane 2x+2y-2z=1
Also find the co-ordinate of the point of division​

Answers

Answered by brokendreams
14

Plane P divides the line AB internally in the ratio 5 : 7. The co-ordinates of the point of division are D = (\frac{29}{12} \ ,\frac{9}{4} \ ,\frac{25}{6} )\\\\

Explanation:

Given:

A\ (2,1,5)(x_1,y_1,z_1)

B\ (3,4,3)(x_2,y_2, z_2)

Plane P = 2x+2y-2z=1 ......................(1)

Let D\ (x_3,y_3, z_3) be the point at which plane P meets the line segment formed by points A and B.

Let the plane P divide line AB in the ratio k:1 ; [m : n = k : 1]

m = k , n = 1

Point D lies on the line AB and also on the plane P. The co-ordinates of D are equal to:

D = (\frac{mx_2 + nx_1}{m+n}\ ,\frac{my_2 + ny_1}{m+n}\ ,\frac{mz_2 + nz_1}{m+n}  )\\\\D = (\frac{3k +2}{k+1}\ ,\frac{4k + 1}{k+1}\ ,\frac{3k + 5}{k+1}  )\\\\..........................(2)

Since point D lies on the plane P, it should satisfy equation (1)

Substituting the values of x, y and z co-ordinates of point D in equation of plane P, we get:

2x+2y-2z=1\\\\2(\frac{3k +2}{k+1})+2(\frac{4k + 1}{k+1})-2(\frac{3k + 5}{k+1})=1\\\\6k+4+8k+2-6k-10=k+1\\8k-4=k+1\\8k-k=4+1\\7k=5\\\\k=\frac{5}{7}

The required ratio is k : 1 , i.e. \frac{5}{7} :1 = 5 : 7

Therefore plane P divides line AB internally in the ratio 5 : 7.

To find the coordinates of point D, substitute the value of k in equation (2)

D = (\frac{3k +2}{k+1}\ ,\frac{4k + 1}{k+1}\ ,\frac{3k + 5}{k+1}  )\\\\D = (\frac{3[\frac{5}{7}]+2}{[\frac{5}{7}]+1}\ ,\frac{4[\frac{5}{7}] + 1}{[\frac{5}{7}]+1}\ ,\frac{3[\frac{5}{7}]+5}{[\frac{5}{7}]+1}  )\\\\  D =  (\frac{[\frac{15+14}{7}]}{[\frac{5+7}{7}]}\ ,\frac{[\frac{20+7}{7}]}{[\frac{5+7}{7}]}\ ,\frac{[\frac{15+35}{7}]}{[\frac{5+7}{7}]}  )\\\\D =  (\frac{[\frac{29}{7}]}{[\frac{12}{7}]}\ ,\frac{[\frac{27}{7}]}{[\frac{12}{7}]}\ ,\frac{[\frac{50}{7}]}{[\frac{12}{7}]}  )\\\\

D = (\frac{29}{12} \ ,\frac{27}{12} \ ,\frac{50}{12} )\\\\

D = (\frac{29}{12} \ ,\frac{9}{4} \ ,\frac{25}{6} )\\\\

Therefore co-ordinates of the point of division D are D = (\frac{29}{12} \ ,\frac{9}{4} \ ,\frac{25}{6} )\\\\

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