Math, asked by ompatelgolya, 2 months ago

23. Find the sum of the first 40 positive integers divisible by 6.

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Answered by ItzzHeartlessBoy

2

We know that the first 40 positive integers divisible by 6 are 6,12,18,....

This is an AP with a = 6 and d = 6.

S40= 20[2(6) +(40-1)6] =20[12+234] =4920.

Answered by Itzabhi001

0

Answer:

sᴇᴇ ᴛʜᴇ ᴀᴛᴛᴀᴄʜᴍᴇɴᴛ

ʜᴏᴘᴇ ɪᴛ ᴡɪʟʟ ʜᴇʟᴘ ʏᴏᴜ

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