Question

23.
Find the values of 'k' for which the given equation has real and equal roots :
(k - 12 )x2 + 2 (k - 12) + 2 = 0
​

Answer 1

Step-by-step explanation:

2k-12+2k-12k=0

-10-10k=0

-10k=10

k is minus 1

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