Question

23. Find the volume of iron required to make an
open box whose external dimensions are 36 cmx
25 cm x 16.5 cm, the box being 1.5 cm thick
throughout. If 1cm of iron weights 8.5 grams,
find the weight of the empty box in kilograms.​

Answer 1

Answer:external vol. -internal vol.=vol. of iron used

vol of iron * weight per unit = weight of empty box

then convert into kg

internal vol.=25-3   =22

                     36-3     =33

                     16.5-1.5   =15

Step-by-step explanation:

Answer 2

Question:

Find the volume of iron required to make an open box whose external dimensions are 36 cm x 25 cm x 16.5 cm, the box being 1.5 cm thick throughout. If 1cm³ of iron weights 8.5 grams, find the weight of the empty box in kilograms.

Answer:

• Weight of the empty box is 33.660kg

Step-by-step Explanation

Given:

• Outer length of open box =36 cm
• Outer breadth =25 cm
• Outer height =16.5 cm
• Thickness of iron =1.5 cm

To find:

• The weight of the empty box in kilograms

Solution:

∴ Inner length =36−(2×1.5)=36−3=33 cm

Inner breadth =25−(2×1.5)=25−3=22 cm

Inner height =16.5−1.5=15 cm

∴ Volume of iron used in it = Outer volume − Inner volume

=36×25×16.5−33×22×15

=14850−10890

=3960 cm³

Now, weight of 1 cm³=8.5 g 

∴ Total weight =3960×8.5 g

=33660 g 

=33.660 kg   [1 kg=1000 g]

• The weight of the empty box is 33.660 kg.

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