Question

23. For which value of k will the quadratic equation 5x2-2kx+3=0 have two real root.​

Answer 1

Let one root of the given that other zero is Reciprocal the one zero.

So,

Other zero=1/Alpa.

Given polynomial is 5x

2

+13x+k=0.

Here,

A=coefficient of x

2

B=coefficient of x

And,C=constant term.

Product of zeroes =C/A

Alpha ×1/Alpha =K/5

1=K/5

K=5

Then,

We get k=5.

Answer 2

Answer:

Given that x-(5/7)-5'(7/5) 7

so,

first of all let the value (5/7y-5 be as it is

and the value (7/5Y-7 is

(6/77

and now

from the question

(5/7145*(5/7/7= it is in the form of

a man is a mountain

so,

it will be becoming as

(5/71-5+7

it is (5/7/2

it is 25/49

and now the value of x is 25/49

and the value of 2x+1

2x+1 is 2(25/49)+1

is equal to 50/49+1

after by the lem

is equal to the 50+49/49

99/49

it is the answer