Question

23) Given thaty = 3 for x = 1 or x varies inversely as y. then find the value of x for y=12.​

Answer 1

x    1          x2

y    3          12

Now, to find x2 we do direct multiplication,

x1 * y1 = x2 * y2

x1=1

y1=3

y2=12

Now put the values,

1*3=_*12

3=_*12

_=$\frac{3}{12}$

_=$\frac{1}{4}$

Therefore x2=$\frac{1}{4}$

Answer 2

Answer:

For y = 12, the value of x is 1/4.

Step-by-step explanation:

Given x varies inversely as y.

When two quantities are inversely proportional, if the value of one quantity is increased then the value of other quantity decreases or vice-versa.

The inverse relation can be written as

$x\propto \dfrac{1}{y} \implies xy=k~(\mbox{a constant})$                                      ....(1)

Given the value of y = 3 for x = 1.

Therefore, from equation (1), we get,

$1\times 3=k\implies k=3$

Given to find the value of x for y=12.​

Using the same equation (1), we can write

$x\times 12=k$

Substituting the value of k = 3, we get

$x\times 12=3\implies x=\dfrac{3}{12} =\dfrac{1}{4}$

Therefore, for y = 12, the value of x is 1/4.

For similar problems:

https://brainly.in/question/14126755

https://brainly.in/question/47691734