Question

23. If A + B = 90°, then sin²A + sin’B = A) 1 B) 0. C) 2 D)​

Answer 1

Answer:

1

Step-by-step explanation:

Given ∠C=90o

From Triangle, 

sinA=ABBC;  sinB=ABAC

⇒sin2A+sin2B

AB2BC2+AB2AC2=AB2BC2+AC2

From △ABC, by using Pythagoras Theorem,

AB2=BC2+AC2

sin2A+sin2B=AB2BC2+AC2=AB2AB2=1