Question

23. If a, ß, y are the zeroes of the cubic polynomial x3 = mx + nx - 1, then:
(a) a + B + y = m, a ß + B y + y a = n, aß y = 1
(b) a + B + y = -m, a ß + B y + y a = n, a ß y = -1
(c) a + B + y = m, a ß + B y + y a = -n, a ß y = 1
(d) α + β + γ = m, αβ + β γ + γα = η, αβγ = -1



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Answer 1

Step-by-step explanation:

(a)ab+b=am ab+by+a=under ay=b1 (b) a+b+y=x -m ab +by +ya = n,a b =y-1 (c)a+b+y=b ab+by +ya =n ay=b1 (d)a+b+y =m a ab+by+ya=n by=-1a