Question

23. If sin (A + B) = 1 and tan (A-B) = 1/√3 find value of A and B
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Answer 1

Answer:

2-2=0

Step-by-step explanation:

Sec(A+B)=1

(A+B)=90 degree ------(1)

tan(A-B)=1/√3

(A-B)=30degree-----(2)

Solving (1) and (2) we get,

A=60degree

B=30degree

1)tanA+cotB

tan 60degree+cot 30degree

√3+√3=2√3

2)secA-cosB

sec 60degree-cosec 30degree

2-2=0

Answer 2

Step-by-step explanation:

If sin (A + B) = 1 and tan (A-B) = 1/√3 find value of A=60 and B=30