Question

23
If sum of the Number 985 and two other
numbers obtained
by arranging the
digits of 985 in cyclic order is divided
by 111, 22 and 37 rispectively. Find
the quotient in each case​

Answer 1

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Step-by-step explanation:

The given numbers are 985, 859 and 598. The quotient obtained when the sum of these three numbers is divided by: 111 As we know that when the sum of three digit numbers in cyclic order is done and then divided by 111, quotient is sum of digits of a number. Quotient = Sum of digits = 22 We know that when the sum of three digit numbers in cyclic order is done and then divided by sum of digits, quotient is 111. Quotient = 111 Here, 3 × 37 = 111 ∴ Quotient = 3 × (Sum of the digits) = 3 × 22 = 66

Answer 2

The given numbers are 985,859 and 598.

The quotient obtained when the sum of these three numbers is divided by 111

We know that when the sum of three-digit numbers in cyclic order is done and then divided by 111, quotient is the sum of digits of a number.

Quotient = Sum of digits =22

22 (Sum of digits)

We know that when the sum of three-digit numbers in cyclic order is done and then divided by the sum of digits, the quotient is 111.

Quotient =111

37

Here, 3×37=111

Hence, quotient =3× (Sum of the digits) =3×22=66