Question

23. If tan A =1 and tan B=/3 then find the value of cos Acos B-sin Asin B.

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Answer 1

Answer:

hence the answer is

1-√3

_____

2√2

Step-by-step explanation:

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Answer 2

Answer:

correction = tan B = 1/√3 Instead of (/3)

Step-by-step explanation:

Given :

Tan A = 1

we know , tan 45° = 1

therefore, A = 45°

Tan B = 1/(√3)

we know, tan 30° = 1/√3

therefore, B = 30°

Now , to find = (cosA.cosB) - (sinA.sinB)

= (cos45° × cos 30°) - ( sin45° × sin30°)

= [(1/√2) × (√3/2)] - [(1/√2) × (1/2)]

= [√3/(2√2)] - [1/2√2]

= [(√3 - 1)/2√2]

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