Question

23. If the parallel sides of a trapezium are 12 cm apart and their sum is 24 cm then
its area is

Answer 1

Answer:

We divide the trapezium into 3 parts: 2 triangles and a rectangle.

Base of triangle =

2

20−10

=5

Height of the triangle and rectangle (h)

2

=13

2

−5

2

⇒(h)

2

=144

⇒h=12

Area of trapezium =

2

1

×(sum of parallel sides) × (height)

=

2

1

×(10+20)×(12)

=180 sq.cm