Question

23. If x = 2 and y = verify that
|x + y = |xl + lyl and 5x * y) = |xl x lyl​

Answer 1

Step-by-step explanation:

in your case you are considering x<0 and y>0 so

x+|x|+y=7 x+|y|-y=6

x+-x+y=7 x+y-y=6

 

but  is not a valid option because you are considering negative values for x.

If x is negative ONLY |x|=-x you cannot change the sign of all Xs