Question

23.
If ( x - a), (x-b) and ( x- c) are the sides of a
triangle such that (x-a) 2 + (x-b)2 + ( x- c)2
= ( x - a) (x-b) + ( x-b) (x-c) + (x-c)(x-a).
Then, the triangle is always a / an
if ( x-a), ( x-b) and ( x- c) are the sides of a
triangle while ( x-a)2 + (x- b)2 + (x-c)2 = (
x-a)(x-b) + ( x- b) (x-c) + ( x- c)(x-a),
then the triangle is always

Scalene, isosceles,
equilateral or right isoceles​

Answer 1

Answer:

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Step-by-step explanation:

ANSWER

Area of △ABP=21×AB×xc

Area of △APC=21×AC×xb

Area of △BPC==21×BC×xa

∴Area of △ABC= Area of (△ABP+△APC+△BPC)

Formula for area of an equilateral triangle=43a2

⇒43(2)2=(21×2×xc)+(21×2×xb)+(21×2×xa)

(∵AB=BC=AC=2)

⇒3=xc+x

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