Question

23.
In the adjoining figure, PQ=PR and QM=MR
hence
[5]
Р P.
R
M
(i) Show that APMQ = APMR
(ü) ZPMQ = ZPMR = 90°
() ZPQM = ZPRM​

Answer 1

Answer:

Step-by-step explanation:

In △PQL and △PRM

⇒  PQ=PR                            [ Given ]

⇒  ∠PQL=∠PRM              [ Base angles of equal side are also equal ]

⇒  QL=MR                           [ Given ]

∴  △PQL≅△PRM             [ By SAS congruence rule ]

⇒  PL=PM                          [ CPCT ]