Question

23. In the figure shown all surfaces are smooth, find the force acting between 4kg block and 10kg block

1) 70 N
2) 40 N
3) 30 N
4) 20 N​

Answer 1

Answer:

By applying force balance equation on all the three free masses

The acceleration of all the three masses =a

Let all the three masses are a system of 20 kg moving in one direction

So, the acceleration of all the masses is same is same as combined mass

a=

totalmass

netforce

a=

6+4+10

100−40

=

20

60

=3

Apply force balance equation for mass 6 kg,

100−N

1

=6×3

100−N

1

=18

N

1

=82N

formass4kg

N

1

−N

2

=4×3

N

1

−N

2

=12

hereN

1

=82N

then,N

2

=82−12=70N

The force acting between 4 kg and 10 kg =N

2

=70 N