Question

23. In the given figure, AB is a chord of a circle
and AOC is its diameter such that
ZACB = 50°. If AT is the tangent to the
circle at point A, then find ZBAT.
С
50°
B
0
A
T​

Answer 1

Answer:

hence ∠BAT=50°

Step-by-step explanation:

In the fig ∠ABC=90( angle in semi circle)

So ∠BAC=90-∠ACB

=90-50=40°

Now ∠CAT is an angle between radius OA and tangent AT

Thus ∠CAT=90

So ∠BAT=∠CAT-∠CAB

=90-40=50°

hence ∠BAT=50°