23.
In the given figure, the equal sides AB and AC of an isosceles triangle ABC are produced to N and
M, respectively such that AN = AM. Prove that MB = NC.
M
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Given : the equal sides AB and AC of an isosceles triangle ABC are produced to N and M, respectively such that AN = AM.
To Find : Prove that MB = NC
Solution:
ABC isosceles triangle
AB = AC
=> ∠ABC = ∠ACB
AN = AM
=> AN - AB = AM - AC
=> BN = CM
∠NBC = 180° - ∠ABC
∠MCB = 180° - ∠ACB
∠ABC = ∠ACB
=> ∠NBC = ∠MCB
Comparing ΔCBN & ΔBCM
CB = BC ( common)
∠NBC = ∠MCB
BN = CM
=> ΔCBN ≅ ΔBCM ( SAS)
=> CN = MB
QED
Hence Proved
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