23. In the rhombus MNOP, MO and NP are the
diagonals. If MN = 5 cm and XN = 4 cm, find the
length of MX where X is the mid point of diagonals.
Answers
Answered by
15
Step-by-step explanation:
check out my picture. I solved it by hand.
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Answered by
8
Answer:
3 cm
Step-by-step explanation:
We know,
In a Rhombus, Diagonals bisect each other at right angle.
So, angle MXN = 90 degree
In triangle MXN, where angle MXN = 90 degree.
By Pythagorean theorem,
(MN) sq =( XN) sq +(MX) sq
=> (5) sq = (4) sq + (MX) sq
=> 25 =16 + (MX) sq
=> (MX) sq =25 - 16
=> (MX) sq = 9
=> MX = 3
Hence, value of MX = 3 cm
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