Question

23. In the rhombus MNOP, MO and NP are the
diagonals. If MN = 5 cm and XN = 4 cm, find the
length of MX where X is the mid point of diagonals.​

Answer 1

Step-by-step explanation:

check out my picture. I solved it by hand.

Answer 2

Answer:

3 cm

Step-by-step explanation:

We know,

In a Rhombus, Diagonals bisect each other at right angle.

So, angle MXN = 90 degree

In triangle MXN, where angle MXN = 90 degree.

By Pythagorean theorem,

(MN) sq =( XN) sq +(MX) sq

=> (5) sq = (4) sq + (MX) sq

=> 25 =16 + (MX) sq

=> (MX) sq =25 - 16

=> (MX) sq = 9

=> MX = 3

Hence, value of MX = 3 cm