23. In the situation shown, the currents through 3 Ω and 2 Ω resistances are in the ratio
(1) 3:2
(3) 4 : 3
(2) 7:4
(4) 3:1
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4) is the answer I hope it is right
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answer is == (3) 4:3
R in series=3ohms
R in parallel=9/4ohms
Total R through it is given by;
R=R(p):R(s)
=3/4
Therefore by ohms law;
V=IR
I=V/R
I=1/R. (V is constant)
I =1/3/4
I=1*4/3
I=4:3. Ans
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