Question

23. In two similar triangles ABC and PQR, if the corresponding altitudes AD and PS are in
the ratio 9:25, find the ratio of the areas of AABC and APQR​

Answer 1

Answer:

When the two triangles are similar then their base are also is same ratio as their altitude.

so area =1/2(base X height ) is proportional to (height)^2

area(ABC)/area(PQR)=((height of ABC)^2)/((height of PQR)^2)

which is equal to 81/625