Question

23. Metallic gold crystallises in fcc lattice with edge
length 4.070 Å. The closet distance between gold
atoms is
(1) 2.878 Å
(2) 8.140 Å
(3) 2.035 Å(در​

Answer 1

Answer:

In FCC, r=

2

2

a

∴r=

2×1.414

4.070

A

∘

=1.439

A

∘

Closest distance between gold atoms =r+r

=2.878

A

∘