Question

23. Ninety-five percent of world trade is moved by sea, by roughly 50 000 tankers, bulk carriers and
container ships. Most of these ships use diesel fuel.
Engineers are planning to develop wind power support for ships. Their proposal is to attach kite
sails to ships and use the wind's power to help reduce diesel consumption and the fuel's impact
on the environment.
Approximately what is the length of the rope for the kite sail, in order to pull the ship at an
angle of o such that sino = cos(135º – 20) and be at a vertical height of 150 m, as shown in the
diagram opposite?
Rope
1150 m​

Answer 1

Rope Length = 150√2  m

Step-by-step explanation:

Sinθ  = Cos(135° -2θ)

as we know that Sinθ  = Cos(90° -θ)

=>  Cos(90° -θ) = Cos(135° -2θ)

=> 90° -θ = 135° -2θ

=> θ = 45°

Sin 45°  = Vertical Height/Rope Length

=> 1/√2 = 150/Rope Length

=> Rope Length = 150√2  m

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