Question

23 no question solve this

Answer 1

When all four sides of a quadrilateral are equal, then it is either a square or a rhombus.

Now, in both cases, the diagonals are perpendicular bisector of each other.

Again from the figure,

∠AOB = ∠BOC = ∠COD = ∠AOD = 90

and AB = BC = CD = DA

Now, from triangle AOB and BOC,

AO = OC

OB = OB   {common}

AB = CD    {given}

So, from SSS congruency,

ΔAOB ≅ ΔBOC

Answer 2

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