Question

23) Percentage error in kinetic energy of a body of
mass (60 + 0.3) kg moving with velocity (25 + 0.1)
m/s is_ %
A) 0.2
B) 0.4
C) 3
D) 1.3​

Answer 1

Explanation:

the answer is option (B) 0.4.....

Answer 2

FORMULA :

kinetic energy = 1/2 m v^2

% error = (0.3/60 + (2)0.1/25 ) x 100

= (1/200 + 1/125) x 100

= 1/2 + 4/5

= (5+8)/10

= 13/10

= 1.3