Question

23] S = The particle speed can never be equal to the wave speed in sine wave if the amplitude is less then wavelength divided by 2p.exe is one S2 = = In a transverse wave of amplitude A, the maximum particle velocity is four times its wave velocity. Then, the waves length of the wave is TA. S3 = The phase difference between two points separated by 1 m in a wave of frequency 120 Hz is 90°. The velocity of the wave is 480 m/s. elle a) FIT lliwgnite airt ni ovawarteven b)TTE art.10.0 on c) TFT ini od d) FFF alm OONS​

Answer 1

Answer:

True

S2 : False

Amplitude of the wave =A

Maximum velocity of wave υmax=4υ (where υ is the wave velocity)

The relation for the maximum velocity is

υmax=4ω

4υ=4ω

ω=4υA

wavelength of the wave is given by

λ=υf=υω2π=2πυ4υA=πA2

Where f is the frequency f=ω2π from ω=2πf

S3 : True

distance between two points Δx=1m frequency n=120Hz

Phase difference ϕ=90∘=0.5π

The relation for the phase difference is

ϕ=2πλ×Δx

or λ=2π×Δxϕ=2π×10.5π=4m

The velocity of wave is given by

υ=nλ

=120×4=480m/s

Explanation:

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