Question

23. The cross-section of a swimming pool is a trapezium ABCD as
shown in the diagram. AB = 16 m, BC = 5 m, AD = 75 cm and
length of the pool is 50 m. Calculate the volume of water it holds.​

Answer 1

Step-by-step explanation:

ANSWER

The cross section of the swimming pool is a trapezium with parallel sides 1.5m and 3m (depth of both ends) and 40m (length of pool) as the ⊥ r distance between ∥ sides.

The width of pool 1.5m can be the length of cross section.

Length of swimming pool=40m

Breadth of the pool=15m

Depth of the pool=1.5m and 3m

∴ Volume of the water=

2

1

[(1.5+3)×40]×15m

3

=

2

1

×4.5×40×15m

3

=1350m

3

Capacity of water in litres =1350×1000litres (1m

3

=1000litres)

=1350000litres