Question

23. The father’s age is six times his son’s age. Four years hence, the age of the father will be

four times his son’s age. The present ages of the son and the father are, respectively

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Answer 1

Step-by-step explanation:

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Answer 2

Answer:

6 and 36

Step-by-step explanation:

Let the present age of father's be x years and present age of son's be y years.

According to the problem

x=6y

After 4 years

x+4=4(y+4)

Hence we get two equations

x=6y ......... (1)

x+4=4(y+4) ..... (2)

Simplifying eq (2)

x+4=4y+16

x−4y=12

Put x=6y in eq (2), we get

6y−4y=12

2y=12

y=6 years

and x=6y=36 years

Present age of son =6 years

and present age of father =36 years