Physics, asked by krishanmeena882459, 2 months ago

23.
The speed of a body of moss 2 kg Charges
from 4 m/s to lo mls in 10 second. Determine
the magnituele of the force​

Answers

Answered by Ekaro
5

Correct Question :

The speed of a body of mass 2 kg changes from 4m/s to 10m/s in 10 seconds. Determine the magnitude of applied force.....

Solution :

Given that,

  • mass of the body = 2kg
  • initial velocity = 4m/s
  • final velocity = 10m/s
  • time interval = 10s

We are asked to find magnitude of applied force.

❖ As per newton's second law of motion, force is defined as the rate of change of linear momentum.

Mathematically, F = dp/dt

  • F denotes force
  • dp denotes change in momentum
  • dt denotes time

We know that momentum is measured as the product of mass and velocity.

Finally, F = m (v - u) / dt

  • v denotes final velocity
  • u denotes initial velocity
  • m denotes mass

By substituting the given values;

➙ F = m (v - u) / dt

➙ F = 2 (10 - 4) / 10

➙ F = 2(6)/10

➙ F = 12/10

F = 1.2 N

Answered by Anonymous
0

Correct Question :

The speed of a body of mass 2 kg changes from 4m/s to 10m/s in 10 seconds. Determine the magnitude of applied force.....

Solution :

Given that,

mass of the body = 2kg

initial velocity = 4m/s

final velocity = 10m/s

time interval = 10s

We are asked to find magnitude of applied force.

❖ As per newton's second law of motion, force is defined as the rate of change of linear momentum.

Mathematically, F = dp/dt

F denotes force

dp denotes change in momentum

dt denotes time

We know that momentum is measured as the product of mass and velocity.

Finally, F = m (v - u) / dt

v denotes final velocity

u denotes initial velocity

m denotes mass

By substituting the given values;

➙ F = m (v - u) / dt

➙ F = 2 (10 - 4) / 10

➙ F = 2(6)/10

➙ F = 12/10

➙ F = 1.2 N

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