Question

23.
The sum and product of the zeroes of a quadratic polynomial
Pix) = ax2 + bx + c are - 3 and 2 respectively. Show that b + c = 5a.
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Answer 1

Given , sum = -3

and product= 2

$p(x) = a {x}^{2} + bx + c \\ \\ so \: sum = - 3 \\ \\ = > \frac{ - b}{a} = - 3 \\ \\ = >b = 3a \\ \\ and \: product = 2 \\ \\ = > \frac{c}{a} = 2 \\ \\ = > c = 2a \\ \\ so \: now \: \\ \\ b + c = 3a + 2a \\ \\ = > b + c = 5a \\ \\ (shown)$

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