Question

23. The sum of first 6 terms of an AP is 42. The ratio of its 11th term to its 33th term is 1:3. Calculate the first term
of an AP​

Answer 1

Step-by-step explanation:

S6=n/2[2a+(n-1)d]

42=6/2[2a+5d]

42=6a+15d

14=2a+5d

a+10d/a+32d=1/3

3a+30d=a+32d

2a-2d=0

2a+5d=14

2a-2d=0

7d=14

d=2

2a-2d=0

2a=4

a=2

Answer 2

Answer:

hope this will help you..